Split function to find the Nth word in a string
--select dbo.Split('abc,def', ',',2) --returns def
Create FUNCTION [dbo].[Split] (@fullString varchar(200), @separator char(1),@wordNo tinyint)
RETURNS VARCHAR(200) -- return_data_type.
AS BEGIN
declare @wordPart varchar(200),
@sepPos int=0,
@wordCount int = 1
while @wordCount <= @wordNo
begin
if @fullString = ''
return null
set @sepPos = CHARINDEX(@separator, @fullString, @sepPos) if @sepPos = 0set @sepPos = len(@fullString)
set @wordPart = SUBSTRING(@fullString, 1, @sepPos)set @fullString = REPLACE(@fullString, @wordPart,'')
set @wordCount = @wordCount +1
end
RETURN replace(@wordPart,',','')
END
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